(x+y)(x^2-3xy+2y^2)=0

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Solution for (x+y)(x^2-3xy+2y^2)=0 equation: 


Simplifying
(x + y)(x2 + -3xy + 2y2) = 0

Reorder the terms:
(x + y)(-3xy + x2 + 2y2) = 0

Multiply (x + y) * (-3xy + x2 + 2y2)
(x(-3xy + x2 + 2y2) + y(-3xy + x2 + 2y2)) = 0
((-3xy * x + x2 * x + 2y2 * x) + y(-3xy + x2 + 2y2)) = 0

Reorder the terms:
((2xy2 + -3x2y + x3) + y(-3xy + x2 + 2y2)) = 0
((2xy2 + -3x2y + x3) + y(-3xy + x2 + 2y2)) = 0
(2xy2 + -3x2y + x3 + (-3xy * y + x2 * y + 2y2 * y)) = 0
(2xy2 + -3x2y + x3 + (-3xy2 + x2y + 2y3)) = 0

Reorder the terms:
(2xy2 + -3xy2 + -3x2y + x2y + x3 + 2y3) = 0

Combine like terms: 2xy2 + -3xy2 = -1xy2
(-1xy2 + -3x2y + x2y + x3 + 2y3) = 0

Combine like terms: -3x2y + x2y = -2x2y
(-1xy2 + -2x2y + x3 + 2y3) = 0

Solving
-1xy2 + -2x2y + x3 + 2y3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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